Average
Average Concept:-
The average of a number is a measure of the central
tendency of a set of numbers.
In other words, it is an estimate of where the
center point of a set of numbers lies.
Average:-It is defined as the ratio of sum of observations
to Number of observations.
Average =
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Sum of observations
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Number of observations
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(1) Average of n natural numbers = (n + 1) / 2
(2) Average of even n natural numbers = (n + 1)
(3) Average of odd n natural numbers = n
(4) If value of each term increases/decreases by k, then the average of the group also
increases/decreases by k.
(5) If we know average of two groups individually, then the average of combined group
cannot be determined.
(6) There are two groups A and B .If A has n1 observations B. has n2 observations and
their averages are x1 and x2 respectively. If we have to find the average of the
Combined group of A and B use the formula
(5) If we know average of two groups individually, then the average of combined group
cannot be determined.
(6) There are two groups A and B .If A has n1 observations B. has n2 observations and
their averages are x1 and x2 respectively. If we have to find the average of the
Combined group of A and B use the formula
Average of whole group =
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(n1x1 + n2x2)
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(n1 + n2)
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Let numbers are x,x+1,x+2,x+3.
Explanation Average = x+(x+1)+(x+2)+(x+3)/4 = 5.5
Explanation Average = x+(x+1)+(x+2)+(x+3)/4 = 5.5
4x + 6 = 22
4x = 16
x = 4
largest number is x+3 = 4+3 = 7
Example 2 :-Average of 4 consecutive odd number is 24 find the smallest number.
Explanation Let numbers are x,x+2,x+4,x+6.
Explanation Let numbers are x,x+2,x+4,x+6.
Average = x+(x+2)+(x+4)+(x+6)/4 = 24
4x + 12 = 96
4x = 84
x = 21
Smallest number = x = 21
Example 3 :-The average age o three boys is 15 years.If their age are in ratio 3:5:7
what is the age o youngest boy.
Explanation Let the ages of three boys be 3x,x,7x
Average age =(3x+5x+7x)/3 = 15
15x=45
x=3
The age o youngest boy is 3x=3*3=9
what is the age o youngest boy.
Explanation Let the ages of three boys be 3x,x,7x
Average age =(3x+5x+7x)/3 = 15
15x=45
x=3
The age o youngest boy is 3x=3*3=9
Example 4 :-There
were 35 students in a hostel. due to the admission
of 7 new students the
expenses for the mess were increased
by 42/- per day while the average
expenditure per head diminished
by Rs 1 .what was the original expenditure of
the mess.
Explanation After the 7 new students, number of students will become 42
Explanation After the 7 new students, number of students will become 42
average expenditure per head = (x-1)
New total expenditure = 42(x-1)
Given that Expenses for the mess were increased
by 42
42(x-1) -35x =84
42x-42-35 =84
7x = 84
x=12
Example 5 :-There are two sections A and B of a class, consisting of 36 and 44 students’
respectively.If the average weight of section A is 40kg and the average weight
of section B is 35kg, find the average weight of the whole class.
Explanation Now n1=36,n2=44,x1=40,x2=35
Average of whole group =(n1x1 + n2x2)/(n1 + n2)
= (36*40 + 44*35)/(36+44)
=2980/80
= 37.25
Example 6 :-In the first 10 overs of a cricket game, the run rate was only 3.2
Example 7 :-The average of 25 results is 18.The average of first twelve of them is 14
and that of last twelve is 17.Find the thirteenth result.
Sum of 25 results is 18*25 = 450
Sum of first twelve results is 14*12 = 168
Sum of last twelve results is 17*12 = 204
Thirteenth result = Sum of 25 results
- (Sum of first twelve results + Sum of last twelve results)
= 450-(168 + 204)
= 450 - 372 = 78
Example 8:-The average of 11 results is 60.The average of first six result is 58
and that of last six is 63.Find the seventh result.
Explanation 1_2_3_4_5_6_7_8_9_10_11
Sum of 11 results is 11*60 = 660
Sum of first six results is 6*58 = 348
Sum of last six results is 6*63 = 378
Seventh result = (Sum of first six results +Sum of last six results)
-Sum of 11 results
= (348 + 378) - 660
= 726 - 660 = 66
Example 5 :-There are two sections A and B of a class, consisting of 36 and 44 students’
respectively.If the average weight of section A is 40kg and the average weight
of section B is 35kg, find the average weight of the whole class.
Explanation Now n1=36,n2=44,x1=40,x2=35
Average of whole group =(n1x1 + n2x2)/(n1 + n2)
= (36*40 + 44*35)/(36+44)
=2980/80
= 37.25
Example 6 :-In the first 10 overs of a cricket game, the run rate was only 3.2
What should be the run rate in the remaining 40 overs to reach
the target of 282 runs.
Explanation the first 10 overs the run was 32
the run rate= 250/40 = 6.2
the first 50 over’s the run was 282
the remaining 40 overs the run was 282-32 = 250
Example 7 :-The average of 25 results is 18.The average of first twelve of them is 14
and that of last twelve is 17.Find the thirteenth result.
Explanation
1_2_3_4_5_6_7_8_9_10_11_12_13_14_15_16_17_18_19_20_21_22_23_24_25
Sum of first twelve results is 14*12 = 168
Sum of last twelve results is 17*12 = 204
Thirteenth result = Sum of 25 results
- (Sum of first twelve results + Sum of last twelve results)
= 450-(168 + 204)
= 450 - 372 = 78
Example 8:-The average of 11 results is 60.The average of first six result is 58
and that of last six is 63.Find the seventh result.
Explanation 1_2_3_4_5_6_7_8_9_10_11
Sum of first six results is 6*58 = 348
Sum of last six results is 6*63 = 378
Seventh result = (Sum of first six results +Sum of last six results)
-Sum of 11 results
= (348 + 378) - 660
= 726 - 660 = 66
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