Problems On Number
Example 1.
A number is as much less than 54 is more than 24.Find the number?
Explanation :-Let the number be x.
Given 54-x = x-24
2x = 54 + 24= 78
x = 78/2= 39
Example 2.
Example 1.
A number is as much less than 54 is more than 24.Find the number?
Explanation :-Let the number be x.
Given 54-x = x-24
2x = 54 + 24= 78
x = 78/2= 39
Example 2.
If the digits of a two-digit number are interchanged, the number so
formed is 18
more than the original number. The sum of digits is 8. What is the
thrice value of
original number?
Explanation :-(1) Let the unit digit of number is y and tens place digit of number is x
Then original number is 10x + y.
Interchanging digit number is 10y + x.
10y + x = 10x + y +18.
-9x + 9y = 18
-x + y = 2 ............(1)
x + y = 8 ...........(2)
2y = 10
y = 5
x = 3
Hence the original number is 10x + y = 10✖ 3 + 5 = 35.
(2) Let the unit digit of number is x
then tens digit f number is 8-x
Then original number is 10(8-x) + x = 80-9x.
Interchanging digit number is 10x + (8-x) = 8 + 9x
8 + 9x = 80 - 9x + 18
18x = 90
x = 5
Hence the original number is 80 - 9x = 80 -9✖ 5 = 35
Example 3.
(2) Let the unit digit of number is x
then tens digit f number is 8-x
Then original number is 10(8-x) + x = 80-9x.
Interchanging digit number is 10x + (8-x) = 8 + 9x
8 + 9x = 80 - 9x + 18
18x = 90
x = 5
Hence the original number is 80 - 9x = 80 -9✖ 5 = 35
Example 3.
Sum of two numbers is 24 and their product is 140,
then find the numbers?
Explanation :- Let one number be x then another number be 24-x.
x✖(24-x) = 140
24x-x2= 140
x✖(24-x) = 140
24x-x2= 140
x2-24x+140=0
x2-14x-10x+140=0
x(x-14)-10(x- 14)=0
(x-14)(x-10) =
x=14, x = 10
Example 4.
x2-14x-10x+140=0
x(x-14)-10(x- 14)=0
(x-14)(x-10) =
x=14, x = 10
Example 4.
The ten’s
place digit of a two digit number is twice the unit’s place digit.
If the sum of this number and the number formed by interchanging the digits is 66.
Find the number?
If the sum of this number and the number formed by interchanging the digits is 66.
Find the number?
Explanation :- Let unit’s place digit of number be x
Ten’s place digit = 2x .
Then original number is 10(2x) + x = 21x.
Interchanging digit number is 10x + 2x = 12x
21x + 12x = 66
33x = 66
x = 2
Hence original number is = 21x= 42
Example 5.
Ten’s place digit = 2x .
Then original number is 10(2x) + x = 21x.
Interchanging digit number is 10x + 2x = 12x
21x + 12x = 66
33x = 66
x = 2
Hence original number is = 21x= 42
Example 5.
The sum of the digits
of a two digit number is 10.
The tens place digit is 4 times the unit place digit. Find the number?
The tens place digit is 4 times the unit place digit. Find the number?
Explanation :- Let unit’s place digit of number be x
and tens place digit of number is 10-x
and tens place digit of number is 10-x
Then original number is 10(10-x)x + x = 100-9x.
10-x = 4x
5x = 10
x = 2
Then original number is 10(10-x)x + x = 100-9x
= 100 -18
= 82
Example 6.
5x = 10
x = 2
Then original number is 10(10-x)x + x = 100-9x
= 100 -18
= 82
Example 6.
The sum of the digits of a two digit number is 9.
If the digits are reversed, the new number is 9 less than 3 times
the original number. Find the original number.
If the digits are reversed, the new number is 9 less than 3 times
the original number. Find the original number.
Explanation :- Let unit’s place digit of number be x
and tens place digit of number is 9-x
and tens place digit of number is 9-x
Then original number is 10(9-x)x + x = 90-9x.
Interchanging digit number is 10x +( 9-x )= 9x + 9
9x+9 = 3(90-9x) - 9
36x = 252
x = 7
Hence original number is = 90-9x = 90-63= 27.
Example 7.
Interchanging digit number is 10x +( 9-x )= 9x + 9
9x+9 = 3(90-9x) - 9
36x = 252
x = 7
Hence original number is = 90-9x = 90-63= 27.
Example 7.
A two-digit number is such that the product of the digit 8.
When 18 is added to the number the digit are reversed. What is the number?
Explanation :- Let unit’s place digit of number be x
then ten’s place digit of number be 8/x
Then original number is 10✖8/x + x = 80/x+x.
Interchanging digit number is 10x +8/x
80/x + x +18 = 10x +8/x
80 +x2+18x = 10x2+8
9x2-18x-72 = 0
x2-2x-8 = 0
x2-4x+2x-8 = 0
x(x-4)+2(x-4)=0
x=4,x=-2
Hence original number is = 80/4 +4 .
Example 8.
Then original number is 10✖8/x + x = 80/x+x.
Interchanging digit number is 10x +8/x
80/x + x +18 = 10x +8/x
80 +x2+18x = 10x2+8
9x2-18x-72 = 0
x2-2x-8 = 0
x2-4x+2x-8 = 0
x(x-4)+2(x-4)=0
x=4,x=-2
Hence original number is = 80/4 +4 .
Example 8.
The
digits of a two-digit number differ by 5. what is the difference between
the
number and the number formed by reversing its digits?
Explanation :- Let unit’s place digit of number be x
and tens place digit of number is 5+x
and tens place digit of number is 5+x
Then original number is 10(5+x)x + x = 50+11x.
Interchanging digit number is 10x +5+x=5+11x
(50+11x)-(5+11x)=45
Hence the number and interchanging number differ by 45.
Interchanging digit number is 10x +5+x=5+11x
(50+11x)-(5+11x)=45
Hence the number and interchanging number differ by 45.
No comments:
Post a Comment