Simple & Compound Interest
Simple Interest:-
12% per annum is Rs. 40 less than the simple interest on the same
sum for 3 and 1/2 years at 10% per annum. Find the sum
Explanation:-Let the sum =.X Difference of SI Between (7/2 -5/2) years = 40
[{x×10×7}/{100×2}] – [{x×12×5}/{100×2}] = 40
{70 x/200 - 60x/200} = 40
10x/200 = 40
x = 800.
Hence Principal = Rs. 800.
Example 5. At what rate percent per annum will a sum of money double in
8 years.
Explanation:- Amount = 2P ,P = P, SI = P , Rate = R %,Time = 8 Years
SI = {(P ✕ R✕ T)/ 100}
P = (P ✕R✕ 8)/ 100
R = 25/2 = 12.5%
Hence Rate = 12.5%
Example 6. The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347.
What is the period (in years) .
Explanation:- P = 30000, CI =4347 ,Amount = P+CI= 30000+4347 = 34347,
Rate = 7 %,Time = ?
T = 2 years
Example 7. What will be the compound interest on a sum of Rs. 25,000 after 3 years
at the rate of 12 % per annum?
Explanation:- P = 25000, CI =? ,Rate = 12 %,Time = 3 years
Example 8. What is the compound interests on Rs. 5000 for 1 and 1/2 years
at 4% per annum compounded half-yearly?
Explanation:- P = 5000, CI =? ,Rate = 4 %,Time = 1 and 1/2 years
Rate = 2% Time = 3 years
Example 9. Simple interest on a certain sum of money for 3 years at 8%
per annum is half the compound interest on Rs. 4000 for 2 years
at 10% per annum. The sum placed on simple interest is.
Explanation:- For CI : P = 4000, Rate = 10 %,Time = 2 years
Simple Interest:-
Simple interest is a method
of calculating the interest charge on a
loan( amount).
Simple interest is calculated on a amount borrowed for entire period at a rate
of interested.
The formula of Simple Interest :-
SI = {(P ✕ R✕ T)/
100}
Where, P = Principal (the original loan)
R = Rate of interest (at which the loan is charged)
T = Time period (the duration for which money is borrowed)
Amount = Principal +SI
Compound Interest :-
Compound interest is calculated on the principal amount and
also on the accumulated
interest of previous
periods.
The formula of Compound Interest :-
Where, P = Principal (the original loan)
R = Rate of interest per year (at which the loan is charged)
Note:-If the interest is compound half yearly Rate will be half and time will be doubled. i.e. formula to be used
If the interest is compound quarterly Rate will be one fourth
and time will be four times.
i.e. formula to be used
If rate of interests are R1 ,R2,R3 for first year second year third year.
Example 1. A sum of Rs. 2500 becomes Rs. 2725 at the end of 3
years
when calculated at simple interest. Find the rate of interest.
Explanation:-Amount = 2725,Principal = 2500
Simple
interest = 2725 – 2500 = 225
Time
= 3 years, Rate=R = ?
Formula SI = {(P ✕ R✕ T)/ 100}
225 = {(2500✕ R✕ 3)/100}
R = (225✕100)/(2500✕3)
R = 3%
Example 2 A sum of money at simple interest amounts to Rs. 815 in 3 years
and to Rs. 854 in 4 years. What is the sum is.
Explanation:-Amount after 3 years = 815
Amount after 4 years = 854,Principal = P = ?
225 = {(2500✕ R✕ 3)/100}
R = (225✕100)/(2500✕3)
R = 3%
Example 2 A sum of money at simple interest amounts to Rs. 815 in 3 years
and to Rs. 854 in 4 years. What is the sum is.
Explanation:-Amount after 3 years = 815
Amount after 4 years = 854,Principal = P = ?
S.I. for 1 year = Rs. (854 -
815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal
= Rs. (815 - 117) = Rs. 698
Hence Principal = Rs. 698
Example 3. Ram took a
loan of Rs. 1200 with simple interest for as many years as the rate of
interest. If he paid Rs. 432 as interest at the end of the loan period, what
was the rate of interest.
Explanation:- P = 1200, SI = 432 Rate = R %,Time = R Years
Formula SI = {(P ✕ R✕ T)/ 100}
432 = {(1200✕ R✕ R)/100}
432 = 12 R2
R2 = 36
R = 6
Hence Rate = 6 %,Time = 6 Years
Example 4. The simple
interest on a certain sum of money for 2 and 1/2 years at12% per annum is Rs. 40 less than the simple interest on the same
sum for 3 and 1/2 years at 10% per annum. Find the sum
[{x×10×7}/{100×2}] – [{x×12×5}/{100×2}] = 40
{70 x/200 - 60x/200} = 40
10x/200 = 40
x = 800.
Hence Principal = Rs. 800.
Example 5. At what rate percent per annum will a sum of money double in
8 years.
Explanation:- Amount = 2P ,P = P, SI = P , Rate = R %,Time = 8 Years
SI = {(P ✕ R✕ T)/ 100}
P = (P ✕R✕ 8)/ 100
R = 25/2 = 12.5%
Hence Rate = 12.5%
Example 6. The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347.
What is the period (in years) .
Explanation:- P = 30000, CI =4347 ,Amount = P+CI= 30000+4347 = 34347,
Rate = 7 %,Time = ?
T = 2 years
Example 7. What will be the compound interest on a sum of Rs. 25,000 after 3 years
at the rate of 12 % per annum?
Explanation:- P = 25000, CI =? ,Rate = 12 %,Time = 3 years
Example 8. What is the compound interests on Rs. 5000 for 1 and 1/2 years
at 4% per annum compounded half-yearly?
Explanation:- P = 5000, CI =? ,Rate = 4 %,Time = 1 and 1/2 years
Rate = 2% Time = 3 years
per annum is half the compound interest on Rs. 4000 for 2 years
at 10% per annum. The sum placed on simple interest is.
Explanation:- For CI : P = 4000, Rate = 10 %,Time = 2 years
For SI: Rate = 8 %,Time = 3 years,SI = 420,P = ?
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