Time & Work
Time and Work problems refers that the amount of work done by an individual or
a group of individuals in one day.
Hence Raj and Ram can do the complete work 8 days .
Time and Work problems refers that the amount of work done by an individual or
a group of individuals in one day.
Points are to be remember on solving questions on time and work
(1) The work to be completed is considered
as one unit.
(2) It is assumed that a person does the same amount
of work each day.
(3) Work and
men are directly proportional.
(4) work and days are directly proportional.
(5) Men and days are inversely proportional.
Concept for solving problems related to Time and Work
Hence Ram and Shyam can do the complete work 45/7 days .Concept for solving problems related to Time and Work
Case I: If
a person completes a piece of work in n days, then work done by person in one day
= (1/n)th part of the work.
Case
II: If a person completes (1/n)th
part of work in one day, then person will
take n days to complete the work.
Example 1 :-If Ram and Shyam can
do a job in 10 days and 18 days independently,
how many days would they take to
complete the same job working simultaneously?
Explanation :-Ram can do a job in 10 days
Hence Ram one day work = 1/10
Shyam can do a job in 18 days
Hence Shyam one day work = 1/18
Ram and Shyam one day work together =1/10 + 1/18
= 14/90 = 7/45
Example 2 :-Raj can finish a
work in 10 days and Ram can finish
the same work in 40 days. If Raj and Ram both work together
then what is the total number of days taken?
Explanation :-Raj can do a job in 10 days
Hence Raj one day work = 1/10
Ram can do a job in 40 days
Hence Shyam one day work = 1/40
Raj and Ram one day work together =1/10 + 1/40
= 5/40 = 1/8
Example 3 :-Shivam, kamal, Yash can finish a piece of work
in 10 days,
12 days and 15 days respectively. If all the three work at it
together,
they are paid Rs.1500 for the whole work. What is the share of Shivam?
Explanation :-Shivam’s 1 day’s work = 1/10
kamal’s
1 day’s work = 1/12
Yash’s
1 day’s work = 1/15
Therefore,
ratio of shares of Shivam, kamal, Yash = Ratio of their 1 day work.
= 1/10 : 1/12 : 1/15
= 6 : 5 : 4
Sum of ratio terms = 6 + 5 + 4
= 15
Shivam gets
=(6/15)*1500 = Rs. 600
Example 4 :-If A & B together can finish a piece of work in 10 days,A alone
can do the same work in 15 days .How many days would B take
to complete the same work.
can do the same work in 15 days .How many days would B take
to complete the same work.
Explanation :-A & B together can finish a piece of work in 10 days
A & B together one day work = 1/10
A can finish a piece of work in 15 days
A one day work = 1/15
A & B together one day work = 1/10
A can finish a piece of work in 15 days
A one day work = 1/15
B one day work in = 1/10 - 1/15 = 1/30
B together can finish a piece of work in 30 days
B together can finish a piece of work in 30 days
Example 5 :-If A & B together can do a piece of work in 18
days,B & C together
can do a piece of work in 24 days,A & C together can do a piece of work
in 36 days. In how many days will A,B and C finish it working together
and separately.
can do a piece of work in 24 days,A & C together can do a piece of work
in 36 days. In how many days will A,B and C finish it working together
and separately.
Explanation :-A + B together can finish a piece of work in 18 days
A + B together one day work =
1/18
B + C together can finish a piece of
work in 24 days
B + C together one day work =
1/24
A + C together can finish a piece of
work in 36 days
A + C together one day work =
1/36
Adding these three
2(A+B+C) together one day work =
1/18 +1/24 +1/36
= 9/72 = 1/8
(A+B+C) together one day work = 1/16
Hence A,B and C finish work together in 16 days
A one day work =(A+B+C) one day work- (B + C) one day work
=/16-1/24 = 1/48
A can finish a piece of work in 48 days
similarly B can finish a piece of work in 28 and 4/5 days
and C can finish a piece of work in 144 days
Example 6 :-If A & B working separately do a piece of work in 9 days,and 12 days
If they work for a day alternately A beginning in how many days work
will be completed.
If they work for a day alternately A beginning in how many days work
will be completed.
Explanation :-A one day work =1/9,B one day work = 1/12
A + B two days work = 1/9 + 1/12 = 7/36
(A + B) 10 days work = 35/36
remaining work = 1-35/36 = 1/136
on eleventh day A turn 1/9 work in 1 day
hence 1/36 work done by A in 1/4 day
Hence the work will be completed in 10 and 1/4 days.
A + B two days work = 1/9 + 1/12 = 7/36
(A + B) 10 days work = 35/36
remaining work = 1-35/36 = 1/136
on eleventh day A turn 1/9 work in 1 day
hence 1/36 work done by A in 1/4 day
Hence the work will be completed in 10 and 1/4 days.
Example 7 :- Ten men can complete a piece of work in 15 days and fifteen women can
complete a same work in 12 days ,if all 10 men and 15 women work
together ,in how many days work will be completed.
Explanation : Ten men one day work =1/15
Fifteen women one day work =1/12
(Ten men +Fifteen women) one day work = 1/15+1/12 = 9/60
= 3/20
Hence 10 men and 15 women work
together will complete the work in 20/3 days
Example 8 :- 45 men can complete a piece of work in 16 days 6 days after they
started working ,30 more men joined them in how many days will they
now to take the complete remaining work..
Explanation : 45 men one day work =1/16
one man one day work =1/(16*45) = 1/720
45 men 6 days work = 6/16 = 3/8
Remaining work = 1-3/8 = 5/8
75 men one day work =75/720 = 5/48
Hence 5/48 work done by them in one day
Hence 5/8 work done by them (48/5)*(5/8) = 6 days
complete a same work in 12 days ,if all 10 men and 15 women work
together ,in how many days work will be completed.
Explanation : Ten men one day work =1/15
Fifteen women one day work =1/12
(Ten men +Fifteen women) one day work = 1/15+1/12 = 9/60
= 3/20
Hence 10 men and 15 women work
together will complete the work in 20/3 days
Example 8 :- 45 men can complete a piece of work in 16 days 6 days after they
started working ,30 more men joined them in how many days will they
now to take the complete remaining work..
Explanation : 45 men one day work =1/16
one man one day work =1/(16*45) = 1/720
45 men 6 days work = 6/16 = 3/8
Remaining work = 1-3/8 = 5/8
75 men one day work =75/720 = 5/48
Hence 5/48 work done by them in one day
Hence 5/8 work done by them (48/5)*(5/8) = 6 days
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